Whole Numbers — Counting, Ordering and Place Value
FreeGrade 5
1. Place Value Up to 6 Digits
In Grade 5 we work with numbers up to 100 000 and beyond. Every digit in a number has a value that depends on its position. This is called place value. Moving one place to the left makes a digit ten times bigger.
We use six columns in our place value table. Each column has its own colour — learn these colours because we use them in every example below:
| Hundred Thousands | Ten Thousands | Thousands | Hundreds | Tens | Units |
|---|---|---|---|---|---|
| 4 | 5 | 3 | 2 | 7 | 6 |
The number shown is 453 276. Here is what each digit is worth:
- The 4 is in the Hundred Thousands column → its value is 400 000
- The 5 is in the Ten Thousands column → its value is 50 000
- The 3 is in the Thousands column → its value is 3 000
- The 2 is in the Hundreds column → its value is 200
- The 7 is in the Tens column → its value is 70
- The 6 is in the Units column → its value is 6
We can write this in expanded notation — splitting the number to show the value of every digit:
453 276 = 400 000 + 50 000 + 3 000 + 200 + 70 + 6
Worked Examples
- 1Place each digit of 806 054 in the correct column:
Hundred Thousands Ten Thousands Thousands Hundreds Tens Units 8 0 6 0 5 4 - 28 is in the Hundred Thousands column → its value is 800 000.
- 30 is in the Ten Thousands column → its value is 0 (there are no ten thousands in this number).
- 46 is in the Thousands column → its value is 6 000.
- 50 is in the Hundreds column → its value is 0 (there are no hundreds in this number).
- 65 is in the Tens column → its value is 50.
- 74 is in the Units column → its value is 4.
- 8Write in expanded notation: 800 000 + 0 + 6 000 + 0 + 50 + 4 = 806 054.
- 1Step 1 — Place 374 812 in the place value table to find where 7 sits:
Hundred Thousands Ten Thousands Thousands Hundreds Tens Units 3 7 4 8 1 2 - 2Step 2 — Read off the column. The digit 7 is in the Ten Thousands column.
- 3Step 3 — Work out the value. A digit in the Ten Thousands column is worth digit × 10 000. So 7 × 10 000 = 70 000.
- 4Answer: The value of the digit 7 in 374 812 is 70 000.
2. Counting Forwards and Backwards
In Grade 5 we count in larger intervals than Grade 4. An interval is the size of the jump between numbers. Each new number in the pattern is found by adding (counting forwards) or subtracting (counting backwards) the same interval.
We count in these intervals:
Revision from Grade 4
- Count in 2s: 2, 4, 6, 8, 10, …
- Count in 3s: 3, 6, 9, 12, 15, …
- Count in 4s: 4, 8, 12, 16, 20, …
- Count in 5s: 5, 10, 15, 20, 25, …
- Count in 10s: 10, 20, 30, 40, 50, …
- Count in 100s: 100, 200, 300, 400, 500, …
- Count in 1 000s: 1 000, 2 000, 3 000, 4 000, 5 000, …
New in Grade 5
- Count in 10 000s: 10 000, 20 000, 30 000, 40 000, 50 000, …
- Count in 100 000s: 100 000, 200 000, 300 000, 400 000, 500 000, …
To continue a pattern, find the interval first — subtract any term from the one after it. Then keep adding or subtracting that interval to get the next numbers in the pattern.
Worked Examples
- 1Step 1 — Identify the interval. We are counting in 10 000s forwards, so the interval is +10 000.
- 2Step 2 — Add the interval to each term:
30 000 + 10 000 = 40 000 - 340 000 + 10 000 = 50 000
- 450 000 + 10 000 = 60 000
- 560 000 + 10 000 = 70 000
- 670 000 + 10 000 = 80 000
- 7Answer: 40 000, 50 000, 60 000, 70 000, 80 000
- 1Step 1 — Identify the interval. We are counting in 100 000s backwards, so the interval is −100 000.
- 2Step 2 — Subtract the interval from each term:
700 000 − 100 000 = 600 000 - 3600 000 − 100 000 = 500 000
- 4500 000 − 100 000 = 400 000
- 5400 000 − 100 000 = 300 000
- 6Answer: 600 000, 500 000, 400 000, 300 000
3. Representing Numbers on a Number Line
Large numbers can be shown on a number line. A number line has marked intervals placed at equal distances apart. To place a number that falls between two markers, you estimate its position by working out how far it sits between those two marked intervals.
How to place a number on a number line:
- Find the two nearest marked intervals on either side of your number.
- Work out how far your number is from each of those two markers.
- Mark its estimated position in the right spot between the two markers.
A useful shortcut: if your number is exactly halfway between two markers, place it right in the middle of that gap. The halfway point between two numbers is found by adding them and dividing by 2.
Worked Examples
- 1Step 1 — Find the nearest marked intervals. The marked intervals on this number line are 0, 10 000, 20 000, 30 000, … 60 000, 70 000, … 100 000. The number 65 000 falls between 60 000 and 70 000.
- 2Step 2 — Find the halfway point. Halfway between 60 000 and 70 000:
(60 000 + 70 000) ÷ 2 = 130 000 ÷ 2 = 65 000. - 3Step 3 — Conclude. Because 65 000 equals the halfway point exactly, it sits right in the middle of the gap.
- 4Answer: 65 000 sits exactly halfway between 60 000 and 70 000.
- 1Step 1 — Find the nearest marked intervals. The marked intervals are 40 000, 41 000, 42 000, … 46 000, 47 000, … 50 000. The number 46 500 falls between 46 000 and 47 000.
- 2Step 2 — Find the halfway point. Halfway between 46 000 and 47 000:
(46 000 + 47 000) ÷ 2 = 93 000 ÷ 2 = 46 500. - 3Step 3 — Conclude. Because 46 500 equals the halfway point exactly, it sits right in the middle of the gap.
- 4Answer: 46 500 sits exactly halfway between 46 000 and 47 000.
Diagram
Number line from 0 to 100 000 in intervals of 10 000 with 65 000 marked halfway between 60 000 and 70 000
4. Comparing, Ordering and Rounding
To compare two numbers, always start at the highest place value column and work right, one column at a time, until you find two digits that are different. That is the deciding column. We show the deciding digit in red and equal digits already checked in blue.
Use these symbols to write your answer:
- < means less than — the open mouth always faces the bigger number
- > means greater than
- = means equal to
To order a list of numbers from smallest to biggest:
Step 1 — Sort by number of digits. Fewer digits = smaller number. A 4-digit number is always smaller than a 5-digit number.
Step 2 — Numbers with the same digit count: compare from the highest column. Find the deciding column to rank them.
Rounding Off
The same rule from Grade 4 applies to larger numbers. Find the deciding digit — the digit immediately to the right of the column you are rounding to.
- Deciding digit 0 – 4 → round down (the rounding column stays the same)
- Deciding digit 5 – 9 → round up (add 1 to the rounding column)
- Replace all digits to the right of the rounding column with 0
The deciding digit is shown in the colour of its place value column:
- Nearest 1 000 → look at the hundreds digit (yellow)
- Nearest 10 000 → look at the thousands digit (orange)
Worked Examples
- 1Step 1 — Count the digits: 74 382 has 5 digits and 74 529 has 5 digits. Same number of digits — compare from the highest column.
- 2Step 2 — Ten thousands: 74 382 vs 74 529. Both have 7 — equal. Move right.
- 3Step 3 — Thousands: 74 382 vs 74 529. Both have 4 — equal. Move right.
- 4Step 4 — Hundreds (deciding column): 74 382 vs 74 529. The digits are 3 and 5. Since 3 < 5, the number 74 382 is smaller.
- 5Answer: 74 529 is bigger. Write as: 74 382 < 74 529.
- 1Step 1 — Count the digits in each number:
• 9 876 → 4 digits (fewest digits = smallest number)
• 52 341 → 5 digits
• 52 099 → 5 digits
• 100 452 → 6 digits (most digits = biggest number) - 2Step 2 — Place the 4-digit and 6-digit numbers: 9 876 is smallest and 100 452 is biggest. The two 5-digit numbers (52 341 and 52 099) sit in between.
- 3Step 3 — Compare the two 5-digit numbers:
52 341 vs 52 099.
Ten thousands: 5 vs 5 — equal. Move right.
Thousands: 52 vs 52 — equal. Move right.
Hundreds: 52 341 vs 52 099. The digits are 3 and 0. Since 0 < 3, the number 52 099 is smaller. - 4Answer: 9 876 < 52 099 < 52 341 < 100 452.
- 1Step 1 — Identify the deciding digit. We are rounding to the nearest 1 000, so we look at the digit one place to the right — the hundreds digit. In 47 836, the hundreds digit is 8.
- 2Step 2 — Apply the rounding rule. The deciding digit is 8. Because 8 is 5 or more, we round up — add 1 to the thousands digit.
- 3Step 3 — Calculate. The thousands digit is 7. Add 1: 7 + 1 = 8. Replace all digits to the right of the thousands column with 0.
- 4Answer: 48 000.
- 1Step 1 — Identify the deciding digit. We are rounding to the nearest 10 000, so we look at the digit one place to the right — the thousands digit. In 234 500, the thousands digit is 4.
- 2Step 2 — Apply the rounding rule. The deciding digit is 4. Because 4 is less than 5, we round down — the ten thousands digit stays the same.
- 3Step 3 — Calculate. The ten thousands digit stays as 3. Replace all digits to the right of the ten thousands column with 0.
- 4Answer: 230 000.
5. Multiples and Factors
A multiple is the result of multiplying a number by any whole number. Multiples are the numbers you say when you count in a times table.
Multiples of 6:
6, 12, 18, 24, 30, 36, …
- A number has infinitely many multiples — the list never ends.
- The first multiple of any number is the number itself (6 × 1 = 6).
A factor of a number is a number that divides into it exactly with no remainder.
Factors of 24:
1, 2, 3, 4, 6, 8, 12, 24
- Every number has at least two factors: 1 and itself.
- To find all factors: divide the number by 1, 2, 3, 4, … in order and write down every number that divides with no remainder.
Worked Examples
- 1Divide 36 by 1: 36 ÷ 1 = 36 exactly ✓ → 1 and 36 are both factors (1 × 36 = 36).
- 2Divide 36 by 2: 36 ÷ 2 = 18 exactly ✓ → 2 and 18 are both factors (2 × 18 = 36).
- 3Divide 36 by 3: 36 ÷ 3 = 12 exactly ✓ → 3 and 12 are both factors (3 × 12 = 36).
- 4Divide 36 by 4: 36 ÷ 4 = 9 exactly ✓ → 4 and 9 are both factors (4 × 9 = 36).
- 5Divide 36 by 5: 36 ÷ 5 = 7.2 ✗ → 5 is not a factor (there is a remainder).
- 6Divide 36 by 6: 36 ÷ 6 = 6 exactly ✓ → 6 is a factor. We stop here because 6 × 6 = 36 — we have now paired up all the factors.
- 7Answer — all factors of 36 in order: 1, 2, 3, 4, 6, 9, 12, 18, 36.
- 1Step 1 — Divide 56 by 7: 56 ÷ 7 = 8. Check: 7 × 8 = 56 exactly ✓ — no remainder.
- 2Step 2 — Conclude: Because 56 ÷ 7 leaves no remainder, 7 divides into 56 exactly.
- 3Answer: Yes, 7 is a factor of 56. We can also write this as 7 × 8 = 56.
6. Prime Numbers
A prime number is a number that has exactly 2 factors — 1 and itself. That is all. Nothing else divides into it exactly.
Examples of prime numbers: 2, 3, 5, 7, 11, 13
A composite number has more than 2 factors — other numbers also divide into it exactly.
Examples of composite numbers: 4 (factors: 1, 2, 4) · 9 (factors: 1, 3, 9) · 15 (factors: 1, 3, 5, 15)
The number 1 is neither prime nor composite. It has only one factor (itself), so it does not fit either definition.
All prime numbers up to 100:
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97
💡 2 is the only even prime number. Every other even number has 2 as a factor — which gives it at least 3 factors — so all other even numbers are composite.
Worked Examples
- 1Step 1 — What to check: A prime number has no factors between 2 and itself. We only need to test divisors up to the square root of 47 (which is about 6.8, so we round up and test every divisor up to 7), so we check 2, 3, 5 and 7.
- 2Step 2 — Test each divisor:
47 ÷ 2 = 23.5 ✗ (not exact)
47 ÷ 3 = 15.67 ✗ (not exact)
47 ÷ 5 = 9.4 ✗ (not exact)
47 ÷ 7 = 6.7 ✗ (not exact) - 3Step 3 — Conclude: No number between 2 and 7 divides into 47 exactly. So 47 has no factors other than 1 and 47.
- 4Answer: Yes, 47 is a prime number — its only factors are 1 and 47.
- 1Step 1 — Test divisors starting from 2: Check whether any number from 2 upwards divides into 51 exactly.
- 2Step 2 — Test 3: 51 ÷ 3 = 17 exactly ✓ — 3 divides into 51 with no remainder.
- 3Step 3 — Conclude: Because 51 has a factor other than 1 and itself, it cannot be prime. Its full list of factors is: 1, 3, 17, 51 — that is 4 factors.
- 4Answer: No, 51 is not a prime number. It is a composite number.
Diagram
A grid of numbers from 1 to 100 with prime numbers highlighted in blue and composite numbers in a lighter colour showing the distribution of primes up to 100